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4s^2-225=0
a = 4; b = 0; c = -225;
Δ = b2-4ac
Δ = 02-4·4·(-225)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*4}=\frac{-60}{8} =-7+1/2 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*4}=\frac{60}{8} =7+1/2 $
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